In the given figure, AB||CD and if ∠CFE=90∘, then ∠FEB= __∘.
As stated in question AB||CD and if ∠CFE = 90∘, so ∠FEB is an alternate angle to ∠CFE which should be equal. So, ∠CFE=90∘.
In the given figure, AB||CD and if ∠CFE=90∘, then ∠FEB= ___ degree.
In the given figure, AB||CD and if ∠CFE=90∘ , then ∠FEB=___ degree.