Question

In the given figure, AB||CD and if $\angle$CFE=${90}^{\circ }$ , then $\angle$FEB=___ degree.

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Answer 1

As stated in the question, AB||CD and $\angle$CFE=${90}^{\circ }$ , so, $\angle$FEB is an alternate angle to $\angle$CFE which should be equal. So, $\angle$CFE=${90}^{\circ }$​.