Question

In the given figure, AB$||$CD, $\angle$ABO$={118}^o$, $\angle$BOD$={152}^o$, find $\angle$ODC.

• A. ${70}^o$
• B. ${80}^o$
• C. ${90}^o$
• D. ${34}^o$

Answer 1

The correct option is C ${90}^o$

If we extend $OD$, then it meets line $AB$ at a point, where it makes angle with $AB$ suppose $\theta$

Then, $\theta =180-(180-118)-(180-152)=118+152-180=270-180={90}^o$

$\because AB||CD$

$\therefore \angle ODC=\theta ={90}^o$