In the given figure, AB || CD, ∠ABO=40∘ and ∠CDO=30∘. If ∠DOB=x, then find the value of x.
A
10∘
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B
70∘
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C
110∘
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D
20∘
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Solution
The correct option is B70∘ Through O draw EOE' parallel to AB & so to CD. ∴∠BOE′=∠ABO=40∘ (alternate angles) ∠E′OD=∠CDO=30∘ alternate angles) ∴∠BOD=(40∘+30∘)=70∘. So, x = 70.