In the given figure- AB CD - - ALC -60- EC is the bisector of - LCD and EF AB- Then- find the measure of - CEF-A- 80-B- 130- 150-D- 120-

The correct option is C 150^∘∠ LCD= ∠ ALC=60^∘ (alternate angles) ∠ DEC=1/2∠ LCD=30^∘. (EC is the angle bisector) ∴ ∠ FEC=(180^∘ 30^∘)=150^∘ ...

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Quantitative Aptitude

Lines and Angles

In the given ...

Question

In the given figure, $A B | | C D, ∠ A L C = 60^{\circ}$ , EC is the bisector of $∠ L C D a n d E F | | A B$ . Then, find the measure of $∠ C E F$ .

80^{\circ}

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130^{\circ}

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120^{\circ}

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150^{\circ}

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Solution

The correct option is D $150^{\circ}$
$∠ L C D = ∠ A L C = 60^{\circ}$ (alternate angles)
$∠ D E C = \frac{1}{2} ∠ L C D = 30^{\circ}$ . (EC is the angle bisector)
$∴ ∠ F E C = (180^{\circ} - 30^{\circ}) = 150^{\circ}$

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In the given figure, AB||CD,∠ALC=60∘, EC is the bisector of ∠LCD and EF||AB. Then, find the measure of ∠CEF.

The correct option is D 150∘∠LCD=∠ALC=60∘ (alternate angles) ∠DEC=12∠LCD=30∘. (EC is the angle bisector) ∴ ∠FEC=(180∘−30∘)=150∘

In the given figure, $A B | | C D, ∠ A L C = 60^{\circ}$ , EC is the bisector of $∠ L C D a n d E F | | A B$ . Then, find the measure of $∠ C E F$ .

The correct option is D $150^{\circ}$
$∠ L C D = ∠ A L C = 60^{\circ}$ (alternate angles)
$∠ D E C = \frac{1}{2} ∠ L C D = 30^{\circ}$ . (EC is the angle bisector)
$∴ ∠ F E C = (180^{\circ} - 30^{\circ}) = 150^{\circ}$