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Question
In the given figure, AB || CD || EF. Find the value of x.
In the given figure, AB || CD || EF. Find the value of x.
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Solution
EF || CD and CE is the traversal.
then
angle ECD + CEF = 180° ( consecutive interior angle)
ECD + 130° = 180°
ECD = 180°-130° = 50°
again AB || CD and BC is transversal.
then,
∠ ABC = ∠ BCD (alternate interior angle)
70° = x° + 50°
(∠ BCD = ∠ BCE + ∠ ECD)
x° = 20°
EF || CD and CE is the traversal.
then
angle ECD + CEF = 180° ( consecutive interior angle)
ECD + 130° = 180°
ECD = 180°-130° = 50°
again AB || CD and BC is transversal.
then,
∠ ABC = ∠ BCD (alternate interior angle)
70° = x° + 50°
(∠ BCD = ∠ BCE + ∠ ECD)
x° = 20°
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