In the given figure, AB||CD. Find the values of x,y and z.
AB ∥ CD and let EF and EG be the transversals.
Now, AB ∥ CD and EF is the transversal.
Then,
∠AEF =∠EFG Alternate Angles
⇒ y° = 75°
Also,
∠EFC + ∠EFD = 180° Since CFD is a straight line
⇒ x + y = 180
⇒ x + 75 = 180
⇒ x = 105
And,
∠EGF + ∠EGD = 180° Since CFGD is a straight line
⇒ ∠EGF + 125 = 180
⇒ ∠EGF = 55°
We know that the sum of angles of a triangle is 180°
∠EFG + ∠GEF + ∠EGF = 180°
⇒ y + z + 55 = 180
⇒ 75 + z + 55 = 180
⇒ z = 50
∴x = 105, y = 75 and z = 50