Question

In the given figure, AB||CD. If $\angle EAB={50}^{\circ }$ and $\angle ECD={60}^{\circ }$ then $\angle AEB=?$

$\left(a\right){50}^{\circ }$

$\left(b\right){60}^{\circ }$

$\left(c\right){70}^{\circ }$

$\left(d\right){55}^{\circ }$

Answer 1

ANSWER:
(c) 70°
AB∥CD and BC is the transversal.
∴∠ABE=∠BCD=60° Alternate Internal Angles
In ∆ABE, we have:
∠EAB+∠ABE+∠AEB=180° (Sum of the angles of a triangle)

⇒50°+60°+∠AEB=180°

⇒∠AEB=70°