In the given figure AB CD- If - EGD -140- and - GHB -4 x - then find the value of x-A- 30- 35-C- 40-D- 45-

The correct option is B 35^∘ Given, AB || CD. nbsp; Also, ∠ EGD = 140^∘ and ∠ GHB = 4x^∘ ∠GHB = ∠EGD (Corresponding angles) ⇒4x = nbsp;140^∘ nbsp; ...

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Byju's Answer

Standard VIII

Mathematics

Properties of Angles Formed by Two Parallel Lines and a Transversal

In the given ...

Question

In the given figure AB || CD. If $∠ E G D = 140^{\circ}$ and $∠ G H B = 4 x^{\circ}$ , then find the value of x.

$30^{\circ}$

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$35^{\circ}$

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$40^{\circ}$

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$45^{\circ}$

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Solution

The correct option is B
$35^{\circ}$

Given, AB || CD.
$Also, ∠ E G D = 140^{\circ} and ∠ G H B = 4 x^{\circ}$

$∠ G H B = ∠ E G D$
(Corresponding angles)

$\Rightarrow 4 x = 140^{\circ}$
$\Rightarrow x = 35^{\circ}$

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In the given figure AB || CD. If ∠EGD=140∘ and ∠GHB=4x∘, then find the value of x.

The correct option is B 35∘ Given, AB || CD. Also, ∠EGD=140∘ and ∠GHB=4x∘ ∠GHB=∠EGD (Corresponding angles) ⇒4x=140∘ ⇒x=35∘

In the given figure AB || CD. If $∠ E G D = 140^{\circ}$ and $∠ G H B = 4 x^{\circ}$ , then find the value of x.

The correct option is B
$35^{\circ}$

Given, AB || CD.
$Also, ∠ E G D = 140^{\circ} and ∠ G H B = 4 x^{\circ}$

$∠ G H B = ∠ E G D$
(Corresponding angles)

$\Rightarrow 4 x = 140^{\circ}$
$\Rightarrow x = 35^{\circ}$