In the given figure, AB || CD. If ∠CAB = 80° and ∠EFC = 25°, then ∠CEF = ?
(a) 65°
(b) 55°
(c) 45°
(d) 75°

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Solution

(c) 45°

$A B ∥ C D and A F$ is the transversal.
$∴ ∠ D C F = ∠ C A B = 80 ° [Corresponding Angles]$
Side EC of triangle EFC is produced to D.
$∴ ∠ C E F + ∠ E F C = ∠ D C F \Rightarrow ∠ C E F + 25 ° = 80 ° \Rightarrow ∠ C E F = 55 °$

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Similar questions

∠ C A B = 80^{o}

∠ E F C = 25^{o}

In the given figure, AB || CD. If $∠ C A B = 180^{\circ}$ and $∠ E F C = 25^{\circ}$ then $∠ C E F = ?$

$(a) 65^{\circ}$

$(b) 55^{\circ}$

$(c) 45^{\circ}$

$(d) 75^{\circ}$

In the given figure, AB || CD. If ∠ABO = 45° and ∠COD = 100°, ∠CDO = ?
(a) 25°
(b) 30°
(c) 35°
(d) 45°

∠ C A B = 80^{\circ}, ∠ C B A = 55^{\circ} a n d ∠ D C A = 45^{\circ}

In the figure below, $△$ ABC $≅$ $△$ BED, $∠$ DEB = $115^{\circ}$ and $∠$ CAB = $25^{\circ}$ , find $∠$ BDE.

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