In the given figure, AB || CD then the value of x is
∠1=45∘ [Alternate angles] ∠2=30∘ [Alternate angles] ∠BOC=∠1+∠2 ∠BOC=45∘+30∘=75∘ So, x=360∘−∠BOC=360∘−75∘=285∘ Hence, x=285∘
In the given figure, AB || CD || EF. Then, the value of x is ____.