In the given figure, AB || CD, then the value of x is
∠1=45∘ [Alternate angles] ∠2=30∘ [Alternate angles] ∠BOC=∠1+∠2 ∠BOC=45∘+30∘=75∘ So, x=360−∠BOC =360−75=285∘ Hence, x=285∘
In the given figure, AB || DE. ∠A=43∘ and ∠BDE=57∘. The value of ∠x is ________.
In the given figure, ABCD is parallelogram.If ∠A=75∘, then ∠B is