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Question

In the given figure, AB || DE, ∠ABC = 70° and ∠CDE = 20°. The measure of ∠BCD is

A
80°
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B
90°
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C
85°
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D
60°
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Solution

The correct option is B 90°
Extending BC such that it intersects DE at F.



Since AB || ED and BF is the transversal.
∴ ∠BFD = ∠ABF (Alternate interior angles)
⇒ ∠BFD = 70°
⇒ ∠CFD = 70°
In ΔCFD,
∠CFD + ∠CDF = ∠BCD (Exterior angle property)
⇒ ∠BCD = 70° + 20° (∵ ∠CDF = 20°)
⇒ ∠BCD = 90°
Thus, the measure of ∠BCD is 90°.
Hence, the correct answer is option (b).

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