Question

In the given figure, AB = EF, BC = DE, AB ⊥ BD and EF ⊥CE. Which of the following criterion is true for ΔABD ΔEFC?

• A. SSS
• B. SAS
• C. AAS
• D. ASA

Answer 1

The correct option is B

SAS

AB = EF ( given)
∠ABD = ∠FEC= 90^o

BC + CD = BD

CD+ DE= CE

or BD = CE

then ∆ABD ≅ ∆EFC
( By SAS ).