Question

In the given figure, AB is a mirror, PO is the incident ray and OR, the reflected ray. If $\angle POR={112}^o$ find $\angle POA$.

• A. ${84}^o$
• B. ${34}^o$
• C. ${54}^o$
• D. ${14}^o$

Answer 1

The correct option is B ${34}^o$

AB is a mirror, PO is the incident ray and OR, the reflected ray.
So, $\angle POA$ and $\angle ROB$ are equal by laws of reflection.
$\angle POR={112}^o$
$=>\angle POA+\angle POR+\angle ROB={180}^0$
$=>\angle POA+{112}^0+\angle POA={180}^0$
$=>2\times \angle POA={68}^0$
$=>\angle POA={34}^0$