Question

In the given figure, $AB$ is a mirror; $PQ$ is the incident ray and $QR$, the reflected ray. If $\angle PQR={112}^o$, finr $\angle PQA$.

Answer 1

As we know that,

angle of incidence $=$ angle of reflection $\left(\text{Law of reflection}\right)$

$\Rightarrow \angle PQA=\angle RQB$

Now,

$\angle PQA+\angle PQR+\angle RQB=180°$

$\Rightarrow \angle PQA+\angle PQA+112°=180°(\because \angle PQA=\angle RQB)$

$\Rightarrow 2\angle PQA=180°-112°$

$\Rightarrow \angle PQA=\frac{68°}{2}=34°$