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Question

In the given figure, AB is a tangent to the circle with centre O. If OP = PC, then OCP = ___.


A

30

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B

45

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C

60

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D

15

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Solution

The correct option is B

45



Since a tangent at any point of a circle is perpendicular to the radius at the point of contact, we have OPC =90.

Since OP = PC, OPC is an isosceles right-angled triangle.
Hence, POC =OCP =45.


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