In the given figure, AB is chord of the circle with centre O, BT is tangent to the circle. The values of x and y are
A
52∘,52∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
58∘,52∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
58∘,58∘
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
60∘,64∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C58∘,58∘ Given AB is a chord of circle and BT is a tangent, ∠BAO=32∘ Here, ∠OBT=90∘ [∵ Tangent is ⊥ to the radius at the point of contact] OA = OB [Radii of the same circle] ∴∠OBA=∠OAB=32∘ [Angles opposite to equal side are equal] ∴∠OBT=∠OBA+∠ABT=90∘or32∘+x=90∘∠x=90∘−32∘=58∘Also,∠AOB=180∘−∠OAB−∠OBA=180∘−32∘−32∘=116∘ Now Y=12∠AOB [Angle formed at the center of a circle is double the angle formed in the remaining part of the circle] =12×116∘=58∘