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Question

In the given figure, AB is chord of the circle with centre O, BT is tangent to the circle. The values of x and y are

A
52,52
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B
58,52
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C
58,58
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D
60,64
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Solution

The correct option is C 58,58
Given AB is a chord of circle and BT is a tangent, BAO=32
Here, OBT=90
[ Tangent is to the radius at the point of contact]
OA = OB [Radii of the same circle]
OBA=OAB=32
[Angles opposite to equal side are equal]
OBT=OBA+ABT=90 or 32+x=90x=9032=58Also,AOB=180OABOBA=1803232=116
Now Y=12AOB
[Angle formed at the center of a circle is double the angle formed in the remaining part of the circle]
=12×116=58

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