Question

In the given figure, AB is one of the diameters of the circle and OC is perpendicular to it through the center O. If AC is, $7\sqrt{2}cm$ then what is the area of the circle in $c{m}^2$.

• A. 24.5
• B. 49
• C. 98
• D. 154

Answer 1

The correct option is D 154

Let the radius of the figure be 'r'.

Then,$A{C}^2=A{O}^2+O{C}^2$ (Pythagorean Theorem)

$Or,(7\sqrt{2}{)}^2=r^2+r^2$

$Or,2r^2=98$

$r=7cm$

Then, Area of the circle $=\pi r^2=\frac{22}{7}\ast 7\ast 7=154c{m}^2$