In the given figure, AB is the diameter of the circle with centre O.

If $∠ A D C = 32^{\circ},$ find angle BOC.

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Solution

$\widehat{AC}$ subtends $AOC$ at the center and $ADC$ at the circumference of the circle.

$\angle AOC = 2 \angle ADC$

$\Rightarrow \angle AOC = 2 \times 32 = 64^o$

$\angle AOC + \angle BOC = 180 \Rightarrow \angle BOC = 180-64=116^o$

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In the given figure, AB is the diameter of the circle with centre O. If ∠ADC=32∘, find angle BOC.

subtends at the center and at the circumference of the circle.

In the given figure, AB is the diameter of the circle with centre O.

If $∠ A D C = 32^{\circ},$ find angle BOC.

$\widehat{AC}$ subtends $AOC$ at the center and $ADC$ at the circumference of the circle.

$\angle AOC = 2 \angle ADC$

$\Rightarrow \angle AOC = 2 \times 32 = 64^o$

$\angle AOC + \angle BOC = 180 \Rightarrow \angle BOC = 180-64=116^o$

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