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B
13o
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C
23o
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D
46o
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Solution
The correct option is B13o Through point E draw a line EF parallel to CD and AB Now, ∠CEF=4x (CD∥EF, corr. ∠s) ∠AEF=6x(EF∥AB, corr. ∠s) Given, ∠CEA=130o⇒∠CEF+∠AEF=130o ⇒4x+6x=130o⇒10x=130o ⇒x=13o