In the given figure, AB∥DC and AD∥BC. If ∠ABC=75∘, then ∠CDA = ___.
In △ABC and △CDA,
(i) ∠BAC = ∠DCA ....(alternate angles)
(ii) AC = AC .......(common)
(iii) ∠BCA=∠DAC .....(alternate angles)
∴ △ABC≅△CDA .....(ASA Postulate)
⇒∠ABC = ∠CDA .......(CPCT)
∴ If ∠ABC = 75∘, then ∠CDA = 75∘.