In the given figure- AB - DC- BO - 6 cm and DO - 8 cm- Find BP - DO-

In the given figure, AB ∥ DC, BO = 6 cm, DO = 8 cm In Δ ODQ and Δ OPB ∠ DOQ = ∠ POB nbsp; nbsp; nbsp; (Vertically opposite angles) ∠ DQO = ∠ OPB nb ...

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Question

In the given figure, $A B ∥ D C$ , BO = 6 cm and DO = 8 cm. Find $B P \times D O$ .

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Solution

In the given figure,

$A B ∥ D C$ ,

BO = 6 cm, DO = 8 cm

In $Δ O D Q$ and $Δ O P B$

$∠ D O Q = ∠ P O B$ (Vertically opposite angles)

$∠ D Q O = ∠ O P B$ (Alternate angles)

$∴ Δ O D Q \sim Δ O P B$

$∴ \frac{D Q}{P B} = \frac{Q O}{O P} = \frac{D O}{O B}$

$\Rightarrow \frac{8}{P B} = \frac{D O}{6}$

By cross multiplication,

$P B \times D O = 8 \times 6 = 48 {cm}^{2}$

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In the given figure, AB∥DC, BO = 6 cm and DO = 8 cm. Find BP×DO.

In the given figure, AB∥DC, BO = 6 cm, DO = 8 cm In ΔODQ and ΔOPB ∠DOQ=∠POB (Vertically opposite angles) ∠DQO=∠OPB (Alternate angles) ∴ΔODQ∼ΔOPB ∴DQPB=QOOP=DOOB ⇒8PB=DO6 By cross multiplication, PB×DO=8×6=48 cm2

In the given figure, $A B ∥ D C$ , BO = 6 cm and DO = 8 cm. Find $B P \times D O$ .