Question

In the given figure, $AB\parallel DE$, then measure of $\angle$ $ACD$ is ____

• A. ${43}^o$
• B. ${40}^o$
• C. ${83}^o$
• D. ${97}^o$

Answer 1

The correct option is C ${83}^o$

As AB || DE, AE is crossing both the parallel lines.
So, $\angle BAE=\angle AED$=40${}^o$
In $△CDE$
$\angle AED+\angle EDC+\angle DCE=180$
$43+40+\angle DCE=180$
$\angle DCE=97$
As ace is straight line
So, $\angle DCE+\angle ACD=180$
$\angle ACD=180-97=83$
Answer (C) $83$