In the given figure, ∠ABC = $90^{\circ}$ and BM is a median (i.e. BM divides the side AC into two equal parts), AB = 4 cm and BC = 3 cm. Then, find the length of AM.

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Solution

$A C = \sqrt{{A B}^{2} + {B C}^{2}}$

$A C = \sqrt{4^{2} + 3^{2}}$ = $\sqrt{25} = 5 c m .$

Since median divides the side in two parts AM = MC

So, AM = MC = 2.5 cm.

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