Question

In the given figure, ABC is a triangle in which 3AD = CD and E lies on BD, DE = 2BE. What is the ratio of area of $\Delta ABE$ and area of $\Delta ABC$ ?

• A. $\frac{1}{12}$
• B. $\frac{1}{3}$
• C. $\frac{1}{2}$
• D. $Noneofthese$

Answer 1

The correct option is A $\frac{1}{12}$

Area of $\Delta BAE=\frac{1}{4}AC\times \frac{1}{3}BD$
$=\frac{1}{12}$ Area of $\Delta ABC$