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Byju's Answer
Standard VIII
Mathematics
Sum of Measures of Exterior Angles of a Polygon
In the given ...
Question
In the given figure
A
B
C
is a triangle in which
A
B
=
A
C
.
X
and
Y
are the Exterior angles formed by producing
A
B
and
A
C
show that
X
=
Y
.
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Solution
A
B
=
A
C
That means
∠
B
=
∠
C
∠
B
=
X
(vertically opposite angles)
∠
C
=
Y
(vertically opposite angles)
X
+
Y
.
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0
Similar questions
Q.
State true or false:
The following figure shows a triangle
A
B
C
with exterior angles as
x
,
y
and
z
.
In the same figure, if
y
>
x
>
z
; arrange sides
A
B
,
B
C
and
A
C
in descending order of their lengths.
And hence answer is
A
B
>
B
C
>
A
C
Q.
In the adjacent figure, ABC is a triangle in which
∠
B
=
50
∘
and
∠
C
=
70
∘
. Sides AB and AC are produced. If 'z' is the measured of the angle between the bisectors of the exterior angles so formed, then
∠
x
∠
y
∠
z are respectively :
Q.
In the figure, ABC is a triangle in which AB = AC. X and Y are points on AB and AC such that AX =AY. Then
Δ
A
B
Y
≅
Δ
A
C
X
Q.
A
B
C
is an isosceles triangle in which
A
B
=
A
C
.
A
D
bisects exterior angle
Q
A
C
and
C
D
∥
B
A
as shown in the figure. Show that
∠
D
A
C
=
∠
B
C
A
Q.
In the adjoining figure, sides
A
B
and
A
C
of
△
A
B
C
are extended to points
P
and
Q
respectively.Also,
∠
P
B
C
<
∠
Q
C
B
. Show that
A
C
>
A
B
.
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Sum of Measures of Exterior Angles of a Polygon
Standard VIII Mathematics
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