Question

In the given figure, ABC is an equilateral triangle with co-ordinates of B and C as B(-3, 0) and C(3, 0). The co-ordinates of the vertex A are ...........

• A. (0, 3 $\sqrt{3}$)
• B. (0, 3)
• C. ($\sqrt{3}$, 3)
• D. (3$\sqrt{3}$, 0)

Answer 1

Answer: (A)

(0, 3 $\sqrt{3}$)

As ABC is an equilateral triangle,
and BC= 6 so, AC= 6,
CO=3, So
$AO=\sqrt{{AC}^2-{OC}^2}=\sqrt{6^2-3^2}$
$AO=\sqrt{36-9}=\sqrt{27}=3\sqrt{3}$
So, here x=0 and
$y=3\sqrt{3}$
Answer (A) (0, 3 $\sqrt{3})$