In the given figure, ABCD and ABEF are two cyclic quadrilateral. If ∠BCD=110∘ then ∠BEF=?
(a) 55∘
(b) 70∘
(c) 90∘
(d) 110∘
ANSWER:
(d) 110°
Since ABCD is a cyclic quadrilateral, we have:
∠BAD + ∠BCD = 180°
⇒ ∠BAD + 110° = 180°
⇒ ∠BAD = (180° - 110°) = 70°
Similarly in ABEF, we have:
∠BAD + ∠BEF = 180°
⇒ 70 ° + ∠BEF = 180°
⇒ ∠BEF = (180° - 70°) = 110°