In the given figure,ABCD and ABFE are parallelograms scuh that ar(quad.EABC)=17 cm2 and ar(||gm ABCD)=25 cm2.Then,ar(△ BCF)=?
(a) 4 cm2
(b) 4.8 cm2
(c) 6 cm2
(d) 8 cm2
(d) 8 cm2
Since ||gm ABCD and ||gm ABFE are on the same base and between the same parallel lines, we have:
ar(||gm ABFE) = ar(||gm ABCD) = 25 cm
⇒ ar(∆BCF ) = ar(||gm ABFE) - ar(quad EABC) = ( 25 - 17) = 8 cm2