In the given figure, ABCD and AEFD are two parallelograms.Prove that,
(i)PE=FQ?
(ii)ar(trianglePEA)=ar(triangleQFD)?
(iii)ar(triangleAPE):ar(triangleQFD):ar(trianglePFD)

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please provide a diagram, as diagrams are always necessary for the solution in geometry

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Q. In the given figure, ABCD and AEFD are two parallelograms. Prove that

(i) PE = FQ

(ii) ar (Δ APE): ar (ΔPFA) = ar Δ (QFD) : ar (Δ PFD)

(iii) ar (Δ PEA) = ar (Δ QFD).

A B C D

and

A E F D

are two

∥^{g m s}

. then

(i)

P E = F Q

(i i)

A r (△ A P E) : A r (△ P F A) = A r (△ Q F D) : A r (△ P F D)

(i i i)

A r (△ P E A) = A r (△ Q F D)

statements are ?

Q. Question 10
In the figure, ABCD and AEFD are two parallelograms. Prove that

a r (Δ P E A) = a r (Δ Q F D)

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In the given figure, ABCD and AEFD are two parallelograms.Prove that, (i)PE=FQ? (ii)ar(trianglePEA)=ar(triangleQFD)? (iii)ar(triangleAPE):ar(triangleQFD):ar(trianglePFD)

please provide a diagram, as diagrams are always necessary for the solution in geometry

In the given figure, ABCD and AEFD are two parallelograms.Prove that,
(i)PE=FQ?
(ii)ar(trianglePEA)=ar(triangleQFD)?
(iii)ar(triangleAPE):ar(triangleQFD):ar(trianglePFD)