In the given figure, ABCD is a cyclic quadrilateral. If ∠BCD = 100° and ∠ABD = 70°, find ∠ADB.

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Solution

It is given that ∠BCD = 100° and ∠ABD = 70°

We have to find the ∠ADB

We have

∠A + ∠C = 180° (Opposite pair of angle of cyclic quadrilateral)

So,

Now in is and

Therefore,

Hence,

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Similar questions

A B C D

∠ B C D = 100^{o}

∠ A B D = 70^{o}

∠ A D B

ABCD is a cyclic quadrilateral. If $∠ B C D = 100^{\circ}$ and $∠ A B D = 70^{\circ},$ then find $∠ A D B .$

In the figure, ABCD is a cyclic quadrilateral, If $∠ B C D = 100^{\circ} a n d ∠ A B D = 70^{\circ}, f i n d ∠ A D B$

∠ B C D = 100^{o}

∠ A B D = 50^{o}

∠ A D B

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