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Sum of Opposite Angles of a Cyclic Quadrilateral

In the given ...

Question

In the given figure, ABCD is a cyclic quadrilateral. If ∠BCD = 100° and ∠ABD = 70°, find ∠ADB.

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Solution

It is given that ∠BCD = 100° and ∠ABD = 70°

We have to find the ∠ADB

We have

∠A + ∠C = 180° (Opposite pair of angle of cyclic quadrilateral)

So,

Now in is and

Therefore,

Hence,

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Sum of Opposite Angles of a Cyclic Quadrilateral

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