In the given figure- ABCD is a field in the form of a quadrilateral whose sides are indicated- If - DAB -90- and DC AB- The area of field is -A- 306 m 2B- 307 m 2C- 309 m 2D- 308 m 2

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Area of Trapezium by Division into Shapes of Known Area

In the given ...

Question

In the given figure, ABCD is a field in the form of a quadrilateral whose sides are indicated. If $∠ D A B = 90^{\circ}$ and $D C | | A B$ . The area of field is :

306 m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

307 m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

308 m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

309 m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $306 m^{2}$

Draw the perpendicular CM on AB from C.
From the figure,
BM =AB –AM =40 -28 =12 m
Area of the field =area of rectangle AMCD +area of right angled triangle MBC
$= 28 \times 9 + \frac{1}{2} \times 12 \times 9 = 306 m^{2}$

Suggest Corrections

Similar questions

In the given figure, ABCD is a field in the form of a quadrilateral whose sides are indicated. If $∠ D A B = 90^{\circ}$ . The area of field is :

Q. In the given figure, ABCD is a field in the form of a quadrilateral whose sides are indicated. If

∠ D A B = 90^{\circ}

. The area of field is :

Q. In fig. ABCD is a field in the form of a quadrilateral whose sides are indicated in the figure. if

∠ D A B = 90^{o}

, find the area of the field.

Answer:

306

m^{2}

State whether answer given is true or not

Q. ABCD is a given field whose sides are indicated. If

∠

DAB = 90

^{o}

, then area of the field is ............

A field is in the shape of a quadrilateral ABCD in which side AB =18 m, side AD=24 m, side BC =40 m, DC =50 m and angle $A = 90^{\circ}$ . Find the area of the field.

Join BYJU'S Learning Program

In the given figure, ABCD is a field in the form of a quadrilateral whose sides are indicated. If ∠DAB=90∘ and DC||AB. The area of field is :

The correct option is A 306m2 Draw the perpendicular CM on AB from C. From the figure, BM =AB –AM =40 -28 =12 m Area of the field =area of rectangle AMCD +area of right angled triangle MBC =28×9+12×12×9=306m2

In the given figure, ABCD is a field in the form of a quadrilateral whose sides are indicated. If $∠ D A B = 90^{\circ}$ and $D C | | A B$ . The area of field is :

The correct option is A $306 m^{2}$

Draw the perpendicular CM on AB from C.
From the figure,
BM =AB –AM =40 -28 =12 m
Area of the field =area of rectangle AMCD +area of right angled triangle MBC
$= 28 \times 9 + \frac{1}{2} \times 12 \times 9 = 306 m^{2}$