Question

In the given figure, ABCD is a field in the form of a quadrilateral whose sides are indicated. If $\angle DAB={90}^{\circ }$ and $DC||AB$. The area of field is :

• A. $306m^2$
• B. $307m^2$
• C. $308m^2$
• D. $309m^2$

Answer 1

The correct option is A $306m^2$


Draw the perpendicular CM on AB from C.
From the figure,
BM =AB –AM =40 -28 =12 m
Area of the field =area of rectangle AMCD +area of right angled triangle MBC
$=28\times 9+\frac{1}{2}\times 12\times 9=306m^2$