Question

In the given figure, ABCD is a parallelogram and ABEF is a rectangle, then

• A. Perimeter of ABCD > Perimeter of ABEF
• B.
• C. Perimeter of ABCD=Perimeter of ABEF
• D. Perimeter of ABCD < Perimeter of ABEF

Answer 1

The correct option is A

Perimeter of ABCD > Perimeter of ABEF

Area of the parallelogram = base $\times$ height
= CD $\times$ EB
Area of rectangle = Length $\times$ Breadth
= EF $\times$ EB
Since the areas are equal, CD $\times$ EB = EF $\times$ EB, CD = EF
Perimeter of the parallelogram ABCD = AB + BC + CD + DA ..........(1)
Perimeter of the rectangle = AB + BE + EF + FA ...........(2)
Comparing .......(1) and .......(2),
BC > BE
AD > FA
AB = AB
CD = EF
So perimeter of parallelogram is greater than perimeter of rectangle