In the given figure, ABCD is a parallelogram. DL is perpendicular to AB and AB = 12 cm. AD = 10 cm. If the area of parallelogram is 156 cm2 then, AL = __
8 cm
Area of parallelogram =Base×corresponding altitude
72=12×DL
DL=6cm
Apply Pythagoras theorem in Triangle DLA
AD2=DL2+AL2
102=62+AL2
100=36+AL2
AL2=64
AL=8cm