You visited us 5 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Parallelogram and Its Properties

In the given ...

Question

In the given figure , ABCD is a parallelogram. DL is perpendicular to AB and AB =AD =13 cm. If the area of the parallelogram is 156cm², then find the length of AL in cm.

___

Open in App

Solution

Area of parallelogram = Base × corresponding altitude

156 = 13×DL

DL = 12 cm

Apply Pythagoras theorem in Triangle DLA

AD² = DL² + AL²

13² = 12² + AL²

AL² = 25

AL = 5 cm

Suggest Corrections

Similar questions

Q. In the given figure,

A B C D

is a parallelogram.

D L ⊥ A B

and

A B = 13

= A D

. If the area of parallelogram is

156 {cm}^{2}

. Then

A L

is _________.

In the given figure, ABCD is a parallelogram. DL is perpendicular to AB and AB = 12 cm. AD = 10 cm. If the area of parallelogram is $156 c m^{2}$ then, AL = __

In the given figure, ABCD is a parallelogram. DL is perpendicular to AB and AB = 12 cm. AD = 10 cm. If the area of parallelogram is $72 c m^{2}$ then, AL = __

Q. In Fig. 21, ABCD is a parallelogram, DL ⊥ AB. If AB = 20 cm, AD = 13 cm and area of the parallelogram is 100 cm², find AL.

Q. In the given figure, ABCD is a parallelogram of area

1470 c m^{2}

D L ⊥ A B

and

B M ⊥ A B

. If

A B = 35

cm and

A D = 49

cm, find DL and BM.

Join BYJU'S Learning Program

In the given figure , ABCD is a parallelogram. DL is perpendicular to AB and AB =AD =13 cm. If the area of the parallelogram is 156cm2, then find the length of AL in cm. ___

Area of parallelogram = Base × corresponding altitude 156 = 13×DL DL = 12 cm Apply Pythagoras theorem in Triangle DLA AD2 = DL2 + AL2 132 = 122 + AL2 AL2 = 25 AL = 5 cm

In the given figure , ABCD is a parallelogram. DL is perpendicular to AB and AB =AD =13 cm. If the area of the parallelogram is 156cm², then find the length of AL in cm.

___

Area of parallelogram = Base × corresponding altitude

156 = 13×DL

DL = 12 cm

Apply Pythagoras theorem in Triangle DLA

AD² = DL² + AL²

13² = 12² + AL²

AL² = 25

AL = 5 cm