In the given figure , ABCD is a parallelogram. DL is perpendicular to AB and AB =AD =13 cm. If the area of the parallelogram is 156cm², then find the length of AL in cm.

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Solution

Area of parallelogram = Base × corresponding altitude

156 = 13×DL

DL = 12 cm

Apply Pythagoras theorem in Triangle DLA

AD² = DL² + AL²

13² = 12² + AL²

AL² = 25

AL = 5 cm

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In the given figure , ABCD is a parallelogram. DL is perpendicular to AB and AB =AD =13 cm. If the area of the parallelogram is 156cm2, then find the length of AL in cm. ___

Area of parallelogram = Base × corresponding altitude 156 = 13×DL DL = 12 cm Apply Pythagoras theorem in Triangle DLA AD2 = DL2 + AL2 132 = 122 + AL2 AL2 = 25 AL = 5 cm

In the given figure , ABCD is a parallelogram. DL is perpendicular to AB and AB =AD =13 cm. If the area of the parallelogram is 156cm², then find the length of AL in cm.

___

Area of parallelogram = Base × corresponding altitude

156 = 13×DL

DL = 12 cm

Apply Pythagoras theorem in Triangle DLA

AD² = DL² + AL²

13² = 12² + AL²

AL² = 25

AL = 5 cm