Question

In the given figure, ABCD is a parallelogram. If $\angle A={75}^{\circ }$, then $\angle B$ is

• A. ${75}^{\circ }$
• B. ${105}^{\circ }$
• C. ${100}^{\circ }$
• D. ${90}^{\circ }$

Answer 1

The correct option is B ${105}^{\circ }$

In a parallelogram, the sum of any two adjacent angles is ${180}^{\circ }.$

$\Rightarrow \angle A+\angle B={180}^{\circ }$

$\Rightarrow {75}^{\circ }+\angle B={180}^{\circ }$

$\Rightarrow \angle B={180}^{\circ }-{75}^{\circ }={105}^{\circ }$