In the given figure, ABCD is a parallelogram in which ∠BDC = 45° and ∠BAD = 75°. Then, ∠CBD = ?
(a) 45°
(b) 55°
(c) 60°
(d) 75°

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Solution

(c) 60°

Explanation:
∠BAD = ∠BCD = 75^o [Opposite angles are equal]
In ∆ BCD, ∠ C = 75^o
∴ ∠CBD = 180^o − (75^o + 45^o) = 60^o

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