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Standard VI

Mathematics

Introduction to Mensuration

In the given ...

Question

In the given figure, ABCD is a parallelogram of area $1470 c m^{2}$ . $D L ⊥ A B$ and $B M ⊥ A B$ . If $A B = 35$ cm and $A D = 49$ cm, find DL and BM.

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Solution

$A B = 35 c m A D = 49 c m$
Area of parallelogram is $1470 c m^{2}$
Area is given as $B a s e \times h e i g h t 35 \times D L = 1470 D L = \frac{1470}{35} = 42 c m$
Area is given as $B a s e \times h e i g h t 49 \times B M = 1470 B M = \frac{1470}{49} = 30 c m$

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Similar questions

Q. In the given figure, ABCD is a parallelogram of area

1470 {c m}^{2} . D L ⊥ A B

and

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DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (see the given figure). If the area of the parallelogram is 1470 cm², AB = 35 cm and AD = 49 cm, find the length of BM and DL.

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and

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Q. DL and BM are the height on sides AB and AD respectively of parallelogram ABCD. If the area of the parallelogram is

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c m^{2}

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Question 6

DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD. If the area of the parallelogram is 1470 ${c m}^{2}$ , AB = 35 cm and AD = 49 cm, find the length of BM and DL.

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In the given figure, ABCD is a parallelogram of area 1470cm2. DL⊥AB and BM⊥AB. If AB=35 cm and AD=49 cm, find DL and BM.

AB=35cmAD=49cmArea of parallelogram is 1470cm2Area is given as Base×height35×DL=1470DL=147035=42cmArea is given as Base×height49×BM=1470BM=147049=30cm

In the given figure, ABCD is a parallelogram of area $1470 c m^{2}$ . $D L ⊥ A B$ and $B M ⊥ A B$ . If $A B = 35$ cm and $A D = 49$ cm, find DL and BM.

$A B = 35 c m A D = 49 c m$
Area of parallelogram is $1470 c m^{2}$
Area is given as $B a s e \times h e i g h t 35 \times D L = 1470 D L = \frac{1470}{35} = 42 c m$
Area is given as $B a s e \times h e i g h t 49 \times B M = 1470 B M = \frac{1470}{49} = 30 c m$