CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In the given figure, ABCD is a parallelogram of base 4 cm and height 4cm , then ar(ΔAFB) is

A
8 cm2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
118 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
67 cm2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 8 cm2
Area of parallelogram ABCD = b×h
=4×4
=16cm2
In Δ ABF and \\gm ABCD, both are having AB as base and lying between the same parallel lines (AB and CD).

( Area of a triangle is half the area of parallelogram if both are on the same base and between the same parallels).

Area of ΔAFB=12× Area of parallelogram ABCD

=12×16=8 cm2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parallelograms on the Same Base and between the Same Parallels Are Equal in Area
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon