Question

# In the given figure, ABCD is a parallelogram of base 4 cm and height 4cm , then ar(ΔAFB) is 8 cm2118 cm25 cm267 cm2

Solution

## The correct option is A 8 cm2Area of parallelogram ABCD = b×h =4×4 =16cm2 In Δ ABF and \\gm ABCD, both are having AB as base and lying between the same parallel lines (AB and CD).   (∵ Area of a triangle is half  the area of parallelogram if both are on the same base and between the same parallels). ∴ Area of ΔAFB=12× Area of parallelogram ABCD                               =12×16=8 cm2

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