Question

In the given figure, ABCD is a parallelogram, then ∠CDB is:

• A. 80^o
• B. 60^o
• C. 100^o
• D. 40^o

Answer 1

The correct option is D

40^o

ABCD is a parallelogram

∠A = ∠C = 60^o ( Opposite angles of a parallelogram are equal )

In ∆BCD, ∠CDB = 180^o - ( 80^o + 60^o ) = 40^o ( Angle sum property of a triangle )