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Question

In the given figure, ABCD is a quadrilateral.

If AB=30cm,, AD=18cm,, BD=24cm,, DC=26cm and DBC=90,

then the area of quadrilateral ABCD = ____ cm2


A
216
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B
300
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C
336
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D
340
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Solution

The correct option is C 336

ABD

S=(18+30+242)

=36cm

Area of △ABD ==S(Sa)(Sb)(Sc)

=36(3624)(3618)(3630)

=(36)(12)(18)(6)

=62×6×2×18×6

=62×62×62

=216cm2

in BDC

BC2=DC2DB2

=262242

=102

BC=10cm

Area of DBC=12×DB×BC

=/1/2×/2412×10

=120cm2
Area of quadrilateral ABCD = Area of △ABD + Area of △DBC

= 216+120

= 336cm2

Hence (C)


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