wiz-icon
MyQuestionIcon
MyQuestionIcon
8
You visited us 8 times! Enjoying our articles? Unlock Full Access!
Question

In the given figure, ABCD is a quadrilateral such that DAAB and CBAB, x = y and EF || AD such that EF bisects DEC. Then CD2 is equal to

A
2CE2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2DE2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Both (a) and (b)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Both (a) and (b)
Given,
ABCD is a quadrilateral with DAAB and CBAB
and EF || AD
EF||BC
EFAB
Now, in ΔDAE and ΔCBE,
DAE=CBE [each 90]
Also, DEA=CEB
ΔDAEΔCBE [by AA similarity]
DEAE=CEBEDE=CE ...(i)
Now, in ΔDEC, right angled at E,
DE2+CE2=DC22DE2=2CE2=DC2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
AA Criterion of Similarity
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon