Question

In the given figure, ABCD is a rhombus in which AC$=$ AB, then $\angle ABC$ equals to :

Answer 1

Since $ABCD$ is a Rhombus then $AB=BC=CD=DA$

But we have $AC=AB$

Therefore, we get $AC=BC$

That is $AB=BC=AC$

$\Rightarrow$ $\Delta ABC$ is a equilateral triangle.

Therefore $\angle ABC=\angle BCD=\angle BAC=60°$

Hence $\angle ABC={60}^{\circ }$