Question

In the given figure, aBCD is a square. Find the measure of $\angle CAD$.

Answer 1

In square ABCD, AC is its diagonal

$\because$ Diagonals of a square bisect each angle at the vertex

$\therefore \angle CAD=\angle CAB$

But $\angle DAB={90}^{\circ }$ (Angle of a square)

$\therefore \angle CAD=\angle CAB=\frac{1}{2}\angle DAB$

= $\frac{1}{2}\times {90}^{\circ }={45}^{\circ }$

Hence$\angle CAD={45}^{\circ }$