Question

Question 84

In the given figure, ABCD is a square with AB = 15 cm. Find the area of the square BDFE.

Answer 1

Given, ABCD is a square and AB = 15 cm
$\therefore$ Diagonal of square $ABCD=\sqrt{2}a=\sqrt{2}\times 15=15\sqrt{2}cm$
From the figure, diagonal of square ABCD is the side of square BDEF.
$\therefore$ Area of the square $BDFE=(Side{)}^2=(15\sqrt{2}{)}^2=15\times 15\times \sqrt{2}\times \sqrt{2}$
$=225\times 2=450c{m}^2$