Question

In the given figure $ABCDE$ is a pentagonal park in which $DE=DC,AB=BC=CE=EA=25m$ and its total height is $41m$. Find the area of the park

• A. $225c{m}^2$
• B. $525c{m}^2$
• C. $625c{m}^2$
• D. $825c{m}^2$

Answer 1

Answer: (D)

$825c{m}^2$

Height of triangle $=41-25=16cm$

Area of park $=$ area of square $ABCE+$ area of $\Delta DEC$

$=25\times 25+\frac{1}{2}\times 25\times 16$

$=625+200$

$=825c{m}^2$