Question

In the given figure, ABP is a straight line and BD||PC.Area $\Delta APD=$___

• A. area $\Delta BPC$
• B. area quadrilateral ABCD
• C. area quadrilateral BPCD
• D. area $\Delta ADC$

Answer 1

The correct option is B

area quadrilateral ABCD

(i)BD ||PC (given)

$\left(ii\right)\therefore$ area $\Delta DBC$ =area $\Delta \left(BDP\right)$

$({\Delta }^{\prime }s$ an the same base and between the same parallels)

(iii)adding area $\Delta ADB$ to both sides we get,area $\Delta ADB$ +area $\Delta DBC$ =area $\Delta ADB$+area $\Delta BDC$ area quadrilateral ABCD =area $\Delta APD$

Hence (b)