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Question

In the given figure, ABP is a straight line and BD||PC.Area ΔAPD=___


A

area ΔBPC

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B

area quadrilateral ABCD

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C

area quadrilateral BPCD

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D

area ΔADC

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Solution

The correct option is C

area quadrilateral ABCD


(i)BD ||PC (given)

(ii) area ΔDBC =area Δ(BDP)

(Δs an the same base and between the same parallels)

(iii)adding area ΔADB to both sides we get,area ΔADB +area ΔDBC =area ΔADB+area ΔBDC area quadrilateral ABCD =area ΔAPD

Hence (b)


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